What is the inverse of f(s)=sqrt(2-3s^{(2))} ?

The inverse of f(s)=sqrt(2-3s^{(2))} is sqrt(-(s^2-2)/3),-sqrt(-(s^2-2)/3)

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inverse of f(s)=sqrt(2-3s^{(2))}

inverse

f (s) = 2 - 3 s^{(2)}

- \frac{s ^{2} - 2}{3}, - - \frac{s ^{2} - 2}{3}

Solution steps

y = 2 - 3 s^{2}

Replace

s

with

y

s = 2 - 3 y^{2}

Solve for

y, s = 2 - 3 y^{2}

- \frac{s ^{2} - 2}{3}, - - \frac{s ^{2} - 2}{3}

- 1 + x

y = \frac{3}{2} x - 1

f (x) = (x - 3)^{2} + 7, x > 3

y = \frac{1}{40} ln (0.1 x) + 30

- 4 x^{2} - 6 x + 3

What is the inverse of f(s)=sqrt(2-3s^{(2))} ?
The inverse of f(s)=sqrt(2-3s^{(2))} is sqrt(-(s^2-2)/3),-sqrt(-(s^2-2)/3)