What is the inverse of 10ln(40x-1200) ?

The inverse of 10ln(40x-1200) is (e^{x/(10)}+1200)/(40)

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inverse of 10ln(40x-1200)

inverse

10 ln (40 x - 1200)

\frac{e ^{\frac{x}{10}} + 1200}{40}

Solution steps

y = 10 ln (40 x - 1200)

Replace

x

with

y

x = 10 ln (40 y - 1200)

Solve for

y, x = 10 ln (40 y - 1200)

\frac{e ^{\frac{x}{10}} + 1200}{40}

sin (\frac{3}{2})

f (x) = - 15 x^{3} + 4

30 x^{10} - 91 x^{5} - 30

f (x) = 1 0^{x - 2} + 4

What is the inverse of 10ln(40x-1200) ?
The inverse of 10ln(40x-1200) is (e^{x/(10)}+1200)/(40)