What is the inverse of f(x)=((4x-2))/(3x+1) ?

The inverse of f(x)=((4x-2))/(3x+1) is (-2-x)/(3x-4)

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inverse of f(x)=((4x-2))/(3x+1)

inverse

f (x) = \frac{( 4 x - 2 )}{3 x + 1}

\frac{- 2 - x}{3 x - 4}

Solution steps

y = \frac{4 x - 2}{3 x + 1}

Replace

x

with

y

x = \frac{4 y - 2}{3 y + 1}

Solve for

y, x = \frac{4 y - 2}{3 y + 1}

\frac{- 2 - x}{3 x - 4}

f (x) = x^{2} - 8 x + 17

f (x) = x^{2} - 8 x + 18

6 x + 7

\frac{1}{10 - 5}

\frac{d}{d} 3 x

What is the inverse of f(x)=((4x-2))/(3x+1) ?
The inverse of f(x)=((4x-2))/(3x+1) is (-2-x)/(3x-4)