What is the inverse of f(x)=3-8x^2 ?

The inverse of f(x)=3-8x^2 is sqrt(-(x-3)/8),-sqrt(-(x-3)/8)

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inverse of f(x)=3-8x^2

inverse

f (x) = 3 - 8 x^{2}

- \frac{x - 3}{8}, - - \frac{x - 3}{8}

Solution steps

y = 3 - 8 x^{2}

Replace

x

with

y

x = 3 - 8 y^{2}

Solve for

y, x = 3 - 8 y^{2}

- \frac{x - 3}{8}, - - \frac{x - 3}{8}

f (x) = x^{2} - 3 x + 6

f (- 8) = \frac{X + 1}{X + 10}

f (x) = \frac{( x + 4 )}{( x + 6 )}

\frac{x + 9}{2}

lo g_{4} (x) + 3

What is the inverse of f(x)=3-8x^2 ?
The inverse of f(x)=3-8x^2 is sqrt(-(x-3)/8),-sqrt(-(x-3)/8)