What is the inverse of f(x)=sqrt(x^3+3) ?

The inverse of f(x)=sqrt(x^3+3) is cube root of x^2-3

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inverse of f(x)=sqrt(x^3+3)

inverse

f (x) = x^{3} + 3

3 x^{2} - 3

Solution steps

y = x^{3} + 3

Replace

x

with

y

x = y^{3} + 3

Solve for

y, x = y^{3} + 3

3 x^{2} - 3

y = \frac{- 9 x - 3}{4}

y = - x^{3}

f (x) = 8 + 4 x - 4

y = x^{2} - 6 x + 11

\frac{x}{8 x - 9}

What is the inverse of f(x)=sqrt(x^3+3) ?
The inverse of f(x)=sqrt(x^3+3) is cube root of x^2-3