What is the inverse of f(x)=sqrt((3x-9)^3) ?

The inverse of f(x)=sqrt((3x-9)^3) is (\sqrt[3]{x^2}+9)/3

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inverse of f(x)=sqrt((3x-9)^3)

inverse

f (x) = (3 x - 9)^{3}

\frac{3 x ^{2} + 9}{3}

Solution steps

y = (3 x - 9)^{3}

Replace

x

with

y

x = (3 y - 9)^{3}

Solve for

y, x = (3 y - 9)^{3}

\frac{3 x ^{2} + 9}{3}

- 3 (- x)^{3}

f (x) = \frac{3 x + 7}{x - 5}

f (x) = x - \frac{6}{2} = 64

y = x + 3 - 4

f (x) = e (3 \cdot tan (3 \cdot x^{3}))

What is the inverse of f(x)=sqrt((3x-9)^3) ?
The inverse of f(x)=sqrt((3x-9)^3) is (\sqrt[3]{x^2}+9)/3