What is the inverse of f(x)=7^{(x^{1/3})/7} ?

The inverse of f(x)=7^{(x^{1/3})/7} is (343ln^3(x))/(ln^3(7))

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inverse of f(x)=7^{(x^{1/3})/7}

inverse

f (x) = 7^{\frac{x ^{\frac{1}{3}}}{7}}

\frac{343 ln ^{3} ( x )}{ln ^{3} ( 7 )}

Solution steps

y = 7^{\frac{x ^{\frac{1}{3}}}{7}}

Replace

x

with

y

x = 7^{\frac{y ^{\frac{1}{3}}}{7}}

Solve for

y, x = 7^{\frac{y ^{\frac{1}{3}}}{7}}

\frac{343 ln ^{3} ( x )}{ln ^{3} ( 7 )}

f (x) = x^{2} - 3, x \geq 0

f (x) = (2 x + 3) = 5 x - 2

f (x) = 3 - lo g_{\frac{1}{5}} (1 + x)

f (x) = - x - 5 + 3

g (x) = x + 6

What is the inverse of f(x)=7^{(x^{1/3})/7} ?
The inverse of f(x)=7^{(x^{1/3})/7} is (343ln^3(x))/(ln^3(7))