What is the inverse of log_{8}(x)= I/(1*10^{-12)} ?

The inverse of log_{8}(x)= I/(1*10^{-12)} is 8^{x*10^{12}}

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inverse of log_{8}(x)= I/(1*10^{-12)}

inverse

lo g_{8} (x) = \frac{I}{1 \cdot 1 0 ^{- 12}}

8^{x \cdot 1 0^{12}}

Solution steps

I = \frac{1}{1 0 ^{12}} lo g_{8} (x)

Replace

x

with

I

x = \frac{1}{1 0 ^{12}} lo g_{8} (I)

Solve for

I, x = \frac{1}{1 0 ^{12}} lo g_{8} (I)

8^{x \cdot 1 0^{12}}

x^{2} - 13

f (x) = \frac{3 x + 11}{6 x + 12}

\frac{- 2 \cdot 5 ^{x}}{3}

f (x) = cos (θ)

f (x) = x^{2} + b x

What is the inverse of log_{8}(x)= I/(1*10^{-12)} ?
The inverse of log_{8}(x)= I/(1*10^{-12)} is 8^{x*10^{12}}