What is the inverse of 4x^2+8x+17 ?

The inverse of 4x^2+8x+17 is (-2+sqrt(x-13))/2 ,-(sqrt(x-13)+2)/2

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inverse of 4x^2+8x+17

inverse

4 x^{2} + 8 x + 17

\frac{- 2 + x - 13}{2}, - \frac{x - 13 + 2}{2}

Solution steps

y = 4 x^{2} + 8 x + 17

Replace

x

with

y

x = 4 y^{2} + 8 y + 17

Solve for

y, x = 4 y^{2} + 8 y + 17

\frac{- 2 + x - 13}{2}, - \frac{x - 13 + 2}{2}

f (x) = 2 (3^{x}) - 4

f (x) = 0.005

f (x) = f (x) = \frac{( 1 )}{( x + 2 )}

y = (ln (x))^{3}

f (x) = - 2 (2 (x - 3)) - 1

What is the inverse of 4x^2+8x+17 ?
The inverse of 4x^2+8x+17 is (-2+sqrt(x-13))/2 ,-(sqrt(x-13)+2)/2