What is the inverse of f(x)=f(x)=((1))/((x+2)) ?

The inverse of f(x)=f(x)=((1))/((x+2)) is 1/x-2

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inverse of f(x)=f(x)=((1))/((x+2))

inverse

f (x) = f (x) = \frac{( 1 )}{( x + 2 )}

\frac{1}{x} - 2

Solution steps

y = \frac{1}{x + 2}

Replace

x

with

y

x = \frac{1}{y + 2}

Solve for

y, x = \frac{1}{y + 2}

\frac{1}{x} - 2

y = (ln (x))^{3}

f (x) = - 2 (2 (x - 3)) - 1

f (x) = \frac{100 ( 1.1 5 ^{x} - 1 )}{0.15}

y = 1 0^{x + 1}

f (x) = 39 x

What is the inverse of f(x)=f(x)=((1))/((x+2)) ?
The inverse of f(x)=f(x)=((1))/((x+2)) is 1/x-2