What is the inverse of f(x)=\sqrt[3]{9}x ?

The inverse of f(x)=\sqrt[3]{9}x is (\sqrt[3]{3}x)/3

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inverse of f(x)=\sqrt[3]{9}x

inverse

f (x) = 39 x

\frac{3 3 x}{3}

Solution steps

y = 39 x

Replace

x

with

y

x = 39 y

Solve for

y, x = 39 y

\frac{3 3 x}{3}

f (x) = 7 sin (x) + 4

y = \frac{x ^{2}}{2} + 2 x

f (x) = - λ (ln (x))

\frac{d}{d} - \frac{1}{x ^{2} + 1}

f (x) = \frac{x - 3}{2 x + 7}

What is the inverse of f(x)=\sqrt[3]{9}x ?
The inverse of f(x)=\sqrt[3]{9}x is (\sqrt[3]{3}x)/3