What is the inverse of y=(x^2)/2+2x ?

The inverse of y=(x^2)/2+2x is (-4+sqrt(16+8x))/2 ,(-4-sqrt(16+8x))/2

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inverse of y=(x^2)/2+2x

inverse

y = \frac{x ^{2}}{2} + 2 x

\frac{- 4 + 16 + 8 x}{2}, \frac{- 4 - 16 + 8 x}{2}

Solution steps

y = \frac{x ^{2}}{2} + 2 x

Replace

x

with

y

x = \frac{y ^{2}}{2} + 2 y

Solve for

y, x = \frac{y ^{2}}{2} + 2 y

\frac{- 4 + 16 + 8 x}{2}, \frac{- 4 - 16 + 8 x}{2}

f (x) = - λ (ln (x))

\frac{d}{d} - \frac{1}{x ^{2} + 1}

f (x) = \frac{x - 3}{2 x + 7}

y = \frac{x - 4}{33 - x}

sin (0.87)

What is the inverse of y=(x^2)/2+2x ?
The inverse of y=(x^2)/2+2x is (-4+sqrt(16+8x))/2 ,(-4-sqrt(16+8x))/2