What is the inverse of y=\sqrt[3]{x-6}+11 ?

The inverse of y=\sqrt[3]{x-6}+11 is x^3-33x^2+363x-1325

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inverse of y=\sqrt[3]{x-6}+11

inverse

y = 3 x - 6 + 11

x^{3} - 33 x^{2} + 363 x - 1325

Solution steps

y = 3 x - 6 + 11

Replace

x

with

y

x = 3 y - 6 + 11

Solve for

y, x = 3 y - 6 + 11

x^{3} - 33 x^{2} + 363 x - 1325

3^{x + 1} - 1

f (x) = - 3 (2 + x)

f (x) = \frac{21}{x ^{2} - 25} - 3

f (x) = ln (x^{2} - 4) + π, x < 2

\frac{5}{x} + 4

What is the inverse of y=\sqrt[3]{x-6}+11 ?
The inverse of y=\sqrt[3]{x-6}+11 is x^3-33x^2+363x-1325