What is the inverse of f(x)=(21)/(x^2-25)-3 ?

The inverse of f(x)=(21)/(x^2-25)-3 is sqrt((25x+96)/(x+3)),-sqrt((25x+96)/(x+3))

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inverse of f(x)=(21)/(x^2-25)-3

inverse

f (x) = \frac{21}{x ^{2} - 25} - 3

\frac{25 x + 96}{x + 3}, - \frac{25 x + 96}{x + 3}

Solution steps

y = \frac{21}{x ^{2} - 25} - 3

Replace

x

with

y

x = \frac{21}{y ^{2} - 25} - 3

Solve for

y, x = \frac{21}{y ^{2} - 25} - 3

\frac{25 x + 96}{x + 3}, - \frac{25 x + 96}{x + 3}

f (x) = ln (x^{2} - 4) + π, x < 2

\frac{5}{x} + 4

f (x) = 15 x^{2} + 2

f (x) = 3 4 - x + 3

f (x) = e^{\frac{( 5 - x ) \cdot l n ( 0.2 )}{5}}

What is the inverse of f(x)=(21)/(x^2-25)-3 ?
The inverse of f(x)=(21)/(x^2-25)-3 is sqrt((25x+96)/(x+3)),-sqrt((25x+96)/(x+3))