What is the inverse of 8(2x+10)^2+3 ?

The inverse of 8(2x+10)^2+3 is (sqrt(2)sqrt(x-3)-40)/8 ,(-sqrt(2)sqrt(x-3)-40)/8

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inverse of 8(2x+10)^2+3

inverse

8 (2 x + 10)^{2} + 3

\frac{2 x - 3 - 40}{8}, \frac{- 2 x - 3 - 40}{8}

Solution steps

y = 8 (2 x + 10)^{2} + 3

Replace

x

with

y

x = 8 (2 y + 10)^{2} + 3

Solve for

y, x = 8 (2 y + 10)^{2} + 3

\frac{2 x - 3 - 40}{8}, \frac{- 2 x - 3 - 40}{8}

f (x) = 5 + 8 y

f (x) = x^{2} - 8 x + 10, x \geq 4

f (x) = x^{2} + 3 x - 21

2 (x - a) (x + 2 a)

f (x) = \frac{2}{x - 5} - 3

What is the inverse of 8(2x+10)^2+3 ?
The inverse of 8(2x+10)^2+3 is (sqrt(2)sqrt(x-3)-40)/8 ,(-sqrt(2)sqrt(x-3)-40)/8