What is the inverse of f(x)=(x+1)/(-2x+1) ?

The inverse of f(x)=(x+1)/(-2x+1) is -(1-x)/(1+2x)

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inverse of f(x)=(x+1)/(-2x+1)

inverse

f (x) = \frac{x + 1}{- 2 x + 1}

- \frac{1 - x}{1 + 2 x}

Solution steps

y = \frac{x + 1}{- 2 x + 1}

Replace

x

with

y

x = \frac{y + 1}{- 2 y + 1}

Solve for

y, x = \frac{y + 1}{- 2 y + 1}

- \frac{1 - x}{1 + 2 x}

f (x) = 1 - 5 x - 5

\frac{3 x ^{2} - 13 x + 4}{2 x ^{2} + 7 x - 15}

f (x) = 9 cos (2 x) + 7, 0 \leq x \leq \frac{π}{2}

\frac{1}{5 x + 3}

f (x) = \frac{x - 1}{x - 1}

What is the inverse of f(x)=(x+1)/(-2x+1) ?
The inverse of f(x)=(x+1)/(-2x+1) is -(1-x)/(1+2x)