What is the inverse of f(x)=-2(x+3)^2-4 ?

The inverse of f(x)=-2(x+3)^2-4 is sqrt(-(x+4)/2)-3,-sqrt(-(x+4)/2)-3

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inverse of f(x)=-2(x+3)^2-4

inverse

f (x) = - 2 (x + 3)^{2} - 4

- \frac{x + 4}{2} - 3, - - \frac{x + 4}{2} - 3

Solution steps

y = - 2 (x + 3)^{2} - 4

Replace

x

with

y

x = - 2 (y + 3)^{2} - 4

Solve for

y, x = - 2 (y + 3)^{2} - 4

- \frac{x + 4}{2} - 3, - - \frac{x + 4}{2} - 3

f (x) = \frac{6 x - 5}{x + 3}

y = \frac{3}{4} x + 2 - 1

y = 1 - \frac{2 - x}{3}

f (- 35) = 3 x - 1

4 z

What is the inverse of f(x)=-2(x+3)^2-4 ?
The inverse of f(x)=-2(x+3)^2-4 is sqrt(-(x+4)/2)-3,-sqrt(-(x+4)/2)-3