What is the inverse of 1/(x^2-16) ?

The inverse of 1/(x^2-16) is sqrt((1+16x)/x),-sqrt((1+16x)/x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of 1/(x^2-16)

inverse

\frac{1}{x ^{2} - 16}

\frac{1 + 16 x}{x}, - \frac{1 + 16 x}{x}

Solution steps

y = \frac{1}{x ^{2} - 16}

Replace

x

with

y

x = \frac{1}{y ^{2} - 16}

Solve for

y, x = \frac{1}{y ^{2} - 16}

\frac{1 + 16 x}{x}, - \frac{1 + 16 x}{x}

f (x) = \frac{4 x - 5}{x - 1}

f (x) = ln (- x + 1)

f (x) = 1 - 3 x^{2}

f (x) = - x + 4

f (x) = 0.5 x^{2} - 7 x + 24.5

What is the inverse of 1/(x^2-16) ?
The inverse of 1/(x^2-16) is sqrt((1+16x)/x),-sqrt((1+16x)/x)