What is the inverse of h(x)=sqrt(x^2-5+2) ?

The inverse of h(x)=sqrt(x^2-5+2) is sqrt(x^2+3),-sqrt(x^2+3)

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inverse of h(x)=sqrt(x^2-5+2)

inverse

h (x) = x^{2} - 5 + 2

x^{2} + 3, - x^{2} + 3

Solution steps

y = x^{2} - 5 + 2

Replace

x

with

y

x = y^{2} - 5 + 2

Solve for

y, x = y^{2} - 5 + 2

x^{2} + 3, - x^{2} + 3

\frac{8}{x ^{2} - x - 6}

f (x) = 4 x + 8 x^{2}

f (x) = - 2^{(x - 2)} + 5

f (5) = 2 x + 1

f (x) = \frac{- 3 x + 9}{x + 7}

What is the inverse of h(x)=sqrt(x^2-5+2) ?
The inverse of h(x)=sqrt(x^2-5+2) is sqrt(x^2+3),-sqrt(x^2+3)