What is the inverse of f(x)=(x^2-8x+12)/(12) ?

The inverse of f(x)=(x^2-8x+12)/(12) is 2(sqrt(3x+1)+2),2(-sqrt(3x+1)+2)

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inverse of f(x)=(x^2-8x+12)/(12)

inverse

f (x) = \frac{x ^{2} - 8 x + 12}{12}

2 (3 x + 1 + 2), 2 (- 3 x + 1 + 2)

Solution steps

y = \frac{x ^{2} - 8 x + 12}{12}

Replace

x

with

y

x = \frac{y ^{2} - 8 y + 12}{12}

Solve for

y, x = \frac{y ^{2} - 8 y + 12}{12}

2 (3 x + 1 + 2), 2 (- 3 x + 1 + 2)

f (x) = x^{2} - 5 x - 8

f (x) = 4 x - \frac{3}{4}

f (x) = \frac{y}{2} - 3

f (x) = 2 π x^{2} + 12 π

f (x) = x^{(2)}, x > 0

What is the inverse of f(x)=(x^2-8x+12)/(12) ?
The inverse of f(x)=(x^2-8x+12)/(12) is 2(sqrt(3x+1)+2),2(-sqrt(3x+1)+2)