What is the inverse of sqrt(4-x^2)+1 ?

The inverse of sqrt(4-x^2)+1 is sqrt(-x^2+2x+3),-sqrt(-x^2+2x+3)

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inverse of sqrt(4-x^2)+1

inverse

4 - x^{2} + 1

- x^{2} + 2 x + 3, - - x^{2} + 2 x + 3

Solution steps

y = 4 - x^{2} + 1

Replace

x

with

y

x = 4 - y^{2} + 1

Solve for

y, x = 4 - y^{2} + 1

- x^{2} + 2 x + 3, - - x^{2} + 2 x + 3

f (x) = 140 - 4.9 t^{2}

- \frac{1}{x - 1} - 3

ln (x) 25.733

211111522 - 322

\frac{- 4 x ^{2} + 2 x}{3 x ^{2} - 1}

What is the inverse of sqrt(4-x^2)+1 ?
The inverse of sqrt(4-x^2)+1 is sqrt(-x^2+2x+3),-sqrt(-x^2+2x+3)