What is the inverse of f(x)=140-4.9t^2 ?

The inverse of f(x)=140-4.9t^2 is sqrt(-(10t-1400)/(49)),-sqrt(-(10t-1400)/(49))

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inverse of f(x)=140-4.9t^2

inverse

f (x) = 140 - 4.9 t^{2}

- \frac{10 t - 1400}{49}, - - \frac{10 t - 1400}{49}

Solution steps

x = 140 - 4.9 t^{2}

Replace

t

with

x

t = 140 - 4.9 x^{2}

Solve for

x, t = 140 - 4.9 x^{2}

- \frac{10 t - 1400}{49}, - - \frac{10 t - 1400}{49}

- \frac{1}{x - 1} - 3

ln (x) 25.733

211111522 - 322

\frac{- 4 x ^{2} + 2 x}{3 x ^{2} - 1}

f (x) = \frac{2 x ^{4} + 7}{x ^{2} + 1}

What is the inverse of f(x)=140-4.9t^2 ?
The inverse of f(x)=140-4.9t^2 is sqrt(-(10t-1400)/(49)),-sqrt(-(10t-1400)/(49))