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Popular >

inverse of f(x)=(2x^4+7)/(x^2+1)

Solution

inverse

f (x) = \frac{2 x ^{4} + 7}{x ^{2} + 1}

Solution

\frac{x + x ^{2} - 8 ( 7 - x )}{2}, - \frac{x + x ^{2} - 8 ( 7 - x )}{2}, \frac{x - x ^{2} - 8 ( 7 - x )}{2}, - \frac{x - x ^{2} - 8 ( 7 - x )}{2}

Solution steps

y = \frac{2 x ^{4} + 7}{x ^{2} + 1}

Replace

x

with

y

x = \frac{2 y ^{4} + 7}{y ^{2} + 1}

Solve for

y, x = \frac{2 y ^{4} + 7}{y ^{2} + 1}

\frac{x + x ^{2} - 8 ( 7 - x )}{2}, - \frac{x + x ^{2} - 8 ( 7 - x )}{2}, \frac{x - x ^{2} - 8 ( 7 - x )}{2}, - \frac{x - x ^{2} - 8 ( 7 - x )}{2}

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Frequently Asked Questions (FAQ)

What is the inverse of f(x)=(2x^4+7)/(x^2+1) ?
The inverse of f(x)=(2x^4+7)/(x^2+1) is