What is the inverse of f(x)=(4x-7)/(3x+1) ?

The inverse of f(x)=(4x-7)/(3x+1) is (-7-x)/(3x-4)

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inverse of f(x)=(4x-7)/(3x+1)

inverse

f (x) = \frac{4 x - 7}{3 x + 1}

\frac{- 7 - x}{3 x - 4}

Solution steps

y = \frac{4 x - 7}{3 x + 1}

Replace

x

with

y

x = \frac{4 y - 7}{3 y + 1}

Solve for

y, x = \frac{4 y - 7}{3 y + 1}

\frac{- 7 - x}{3 x - 4}

8 (18 x - 5)^{2} - 2 (18 x - 5)

f (x) = \frac{ln ( x + 2 )}{2} - \frac{3}{4}

f (x) = 4 x^{7} - 1

f (x) = - (x + 1)^{2} + 25

11 - 5 x^{3}

What is the inverse of f(x)=(4x-7)/(3x+1) ?
The inverse of f(x)=(4x-7)/(3x+1) is (-7-x)/(3x-4)