What is the inverse of (x^3+3x^2-9x-2)/(x-2) ?

The inverse of (x^3+3x^2-9x-2)/(x-2) is (-5+sqrt(4x+21))/2 ,(-5-sqrt(4x+21))/2

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inverse of (x^3+3x^2-9x-2)/(x-2)

inverse

\frac{x ^{3} + 3 x ^{2} - 9 x - 2}{x - 2}

\frac{- 5 + 4 x + 21}{2}, \frac{- 5 - 4 x + 21}{2}

Solution steps

y = \frac{x ^{3} + 3 x ^{2} - 9 x - 2}{x - 2}

Replace

x

with

y

x = \frac{y ^{3} + 3 y ^{2} - 9 y - 2}{y - 2}

Solve for

y, x = \frac{y ^{3} + 3 y ^{2} - 9 y - 2}{y - 2}

\frac{- 5 + 4 x + 21}{2}, \frac{- 5 - 4 x + 21}{2}

f (x) = (\frac{x}{4} - 5)^{\frac{1}{3}} + \frac{3}{7}

f (x) = 2 e^{4 x} + 1

f (x) = - 2 x^{2} - 3 x - 1

f (x) = - \frac{4}{5} x^{2} + 29.6 x

g (x) = \frac{9 ( 4 x - 9 )}{4} + 17

What is the inverse of (x^3+3x^2-9x-2)/(x-2) ?
The inverse of (x^3+3x^2-9x-2)/(x-2) is (-5+sqrt(4x+21))/2 ,(-5-sqrt(4x+21))/2