What is the inverse of f(x)=((7x-x^2))/(7-2x) ?

The inverse of f(x)=((7x-x^2))/(7-2x) is -(-7-2x+sqrt(4x^2+49))/2 ,-(-7-2x-sqrt(4x^2+49))/2

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inverse of f(x)=((7x-x^2))/(7-2x)

inverse

f (x) = \frac{( 7 x - x ^{2} )}{7 - 2 x}

- \frac{- 7 - 2 x + 4 x ^{2} + 49}{2}, - \frac{- 7 - 2 x - 4 x ^{2} + 49}{2}

Solution steps

y = \frac{7 x - x ^{2}}{7 - 2 x}

Replace

x

with

y

x = \frac{7 y - y ^{2}}{7 - 2 y}

Solve for

y, x = \frac{7 y - y ^{2}}{7 - 2 y}

- \frac{- 7 - 2 x + 4 x ^{2} + 49}{2}, - \frac{- 7 - 2 x - 4 x ^{2} + 49}{2}

4096

\frac{2 S + 2}{S ^{2} + 4}

f (x) = tan (- \frac{3}{3})

f (x) = \frac{( b ^{2} + 1 )}{b}

f (x) = \frac{3 x + 8}{x - 7}

What is the inverse of f(x)=((7x-x^2))/(7-2x) ?
The inverse of f(x)=((7x-x^2))/(7-2x) is -(-7-2x+sqrt(4x^2+49))/2 ,-(-7-2x-sqrt(4x^2+49))/2