What is the inverse of 1/((s+1)^4) ?

The inverse of 1/((s+1)^4) is \sqrt[4]{1/s}-1,-\sqrt[4]{1/s}-1

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inverse of 1/((s+1)^4)

inverse

\frac{1}{( s + 1 ) ^{4}}

Solution steps

y = \frac{1}{( s + 1 ) ^{4}}

Replace

s

with

y

s = \frac{1}{( y + 1 ) ^{4}}

Solve for

y, s = \frac{1}{( y + 1 ) ^{4}}

(x^{4} + 8)^{- 1}

\frac{8 x - 3}{4 x - 1}

x - 25

y = - \frac{2}{3} (x + 2) (x - 8)

y = - 60 (x - 3)^{2} - 50

What is the inverse of 1/((s+1)^4) ?
The inverse of 1/((s+1)^4) is \sqrt[4]{1/s}-1,-\sqrt[4]{1/s}-1