What is the inverse of f(x)=\sqrt[3]{x^2+7} ?

The inverse of f(x)=\sqrt[3]{x^2+7} is sqrt(x^3-7),-sqrt(x^3-7)

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inverse of f(x)=\sqrt[3]{x^2+7}

inverse

f (x) = 3 x^{2} + 7

x^{3} - 7, - x^{3} - 7

Solution steps

y = 3 x^{2} + 7

Replace

x

with

y

x = 3 y^{2} + 7

Solve for

y, x = 3 y^{2} + 7

x^{3} - 7, - x^{3} - 7

f (x) = y - 2 y

f (x) = \frac{e ^{x} + 1}{e ^{x}}

y = 2 (x - 3)^{2} + 4

\frac{3 x - 5}{2 x + 1}

f (x) = \frac{3 x - 7}{5 x + 2}

What is the inverse of f(x)=\sqrt[3]{x^2+7} ?
The inverse of f(x)=\sqrt[3]{x^2+7} is sqrt(x^3-7),-sqrt(x^3-7)