What is the inverse of f(x)=\sqrt[3]{x^2+3} ?

The inverse of f(x)=\sqrt[3]{x^2+3} is sqrt(x^3-3),-sqrt(x^3-3)

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inverse of f(x)=\sqrt[3]{x^2+3}

inverse

f (x) = 3 x^{2} + 3

x^{3} - 3, - x^{3} - 3

Solution steps

y = 3 x^{2} + 3

Replace

x

with

y

x = 3 y^{2} + 3

Solve for

y, x = 3 y^{2} + 3

x^{3} - 3, - x^{3} - 3

\frac{13}{x ^{2}}

\frac{16 a ^{4} + 16 a}{a ^{2} + 1 - a}

y = ln (\frac{x}{x - 1})

f (x) = \frac{8 x - 7}{7 x + 3}

f (p) = p - 38

What is the inverse of f(x)=\sqrt[3]{x^2+3} ?
The inverse of f(x)=\sqrt[3]{x^2+3} is sqrt(x^3-3),-sqrt(x^3-3)