What is the inverse of f(x)=sqrt(8x-5)+18 ?

The inverse of f(x)=sqrt(8x-5)+18 is (x^2-36x+329)/8

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inverse of f(x)=sqrt(8x-5)+18

inverse

f (x) = 8 x - 5 + 18

\frac{x ^{2} - 36 x + 329}{8}

Solution steps

y = 8 x - 5 + 18

Replace

x

with

y

x = 8 y - 5 + 18

Solve for

y, x = 8 y - 5 + 18

\frac{x ^{2} - 36 x + 329}{8}

f (x) = \frac{7}{4} x + 8

f (x) = 2 \frac{- x ^{2}}{2}

f (x) = x - 4 + 7

f (x) = f (x) = 600 - 2 t^{2}

f (x) = cot (5 x)

What is the inverse of f(x)=sqrt(8x-5)+18 ?
The inverse of f(x)=sqrt(8x-5)+18 is (x^2-36x+329)/8