What is the inverse of f(x)=f(x)=600-2t^2 ?

The inverse of f(x)=f(x)=600-2t^2 is sqrt(-(t-600)/2),-sqrt(-(t-600)/2)

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inverse of f(x)=f(x)=600-2t^2

inverse

f (x) = f (x) = 600 - 2 t^{2}

- \frac{t - 600}{2}, - - \frac{t - 600}{2}

Solution steps

x = 600 - 2 t^{2}

Replace

t

with

x

t = 600 - 2 x^{2}

Solve for

x, t = 600 - 2 x^{2}

- \frac{t - 600}{2}, - - \frac{t - 600}{2}

f (x) = cot (5 x)

f (x) = (\frac{( x - 5 )}{2})^{7}

f (x) = \frac{1}{3} lo g_{10} (5 x)

y = - 35 x - 46.716

f (x) = \frac{x ^{2} + 4 x - 5}{x ^{2} - 7 x + 6}

What is the inverse of f(x)=f(x)=600-2t^2 ?
The inverse of f(x)=f(x)=600-2t^2 is sqrt(-(t-600)/2),-sqrt(-(t-600)/2)