What is the inverse of y=(4x-7)/(2x+3) ?

The inverse of y=(4x-7)/(2x+3) is (-7-3x)/(2(-2+x))

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inverse of y=(4x-7)/(2x+3)

inverse

y = \frac{4 x - 7}{2 x + 3}

\frac{- 7 - 3 x}{2 ( - 2 + x )}

Solution steps

y = \frac{4 x - 7}{2 x + 3}

Replace

x

with

y

x = \frac{4 y - 7}{2 y + 3}

Solve for

y, x = \frac{4 y - 7}{2 y + 3}

\frac{- 7 - 3 x}{2 ( - 2 + x )}

f (x) = \frac{2}{x} + x

f (x) = \frac{2}{π}

g (x) = \frac{1}{x - 1} f (x) = \frac{x + 1}{1}

f (x) = \frac{3 6 ^{x}}{5}

\frac{1}{a}

What is the inverse of y=(4x-7)/(2x+3) ?
The inverse of y=(4x-7)/(2x+3) is (-7-3x)/(2(-2+x))