What is the inverse of-3(x+4)^2-1 ?

The inverse of-3(x+4)^2-1 is sqrt(-(x+1)/3)-4,-sqrt(-(x+1)/3)-4

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inverse of-3(x+4)^2-1

inverse

- 3 (x + 4)^{2} - 1

- \frac{x + 1}{3} - 4, - - \frac{x + 1}{3} - 4

Solution steps

y = - 3 (x + 4)^{2} - 1

Replace

x

with

y

x = - 3 (y + 4)^{2} - 1

Solve for

y, x = - 3 (y + 4)^{2} - 1

- \frac{x + 1}{3} - 4, - - \frac{x + 1}{3} - 4

(21) (34)

f (x) = (\frac{2}{s ^{2}}) - (\frac{2}{s ^{2}})

- \frac{4}{x - 1}

f (x) = \frac{x ^{2} + 3}{3 + x}

What is the inverse of-3(x+4)^2-1 ?
The inverse of-3(x+4)^2-1 is sqrt(-(x+1)/3)-4,-sqrt(-(x+1)/3)-4