What is the inverse of y=(-4x^2+28x+31)/(16) ?

The inverse of y=(-4x^2+28x+31)/(16) is -(-7+4sqrt(-x+5))/2 ,(4sqrt(-x+5)+7)/2

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inverse of y=(-4x^2+28x+31)/(16)

inverse

y = \frac{- 4 x ^{2} + 28 x + 31}{16}

- \frac{- 7 + 4 - x + 5}{2}, \frac{4 - x + 5 + 7}{2}

Solution steps

y = \frac{- 4 x ^{2} + 28 x + 31}{16}

Replace

x

with

y

x = \frac{- 4 y ^{2} + 28 y + 31}{16}

Solve for

y, x = \frac{- 4 y ^{2} + 28 y + 31}{16}

- \frac{- 7 + 4 - x + 5}{2}, \frac{4 - x + 5 + 7}{2}

f (x) = \frac{5}{3} + 5

f (x) = 9 - x + 6

tan (- \frac{4}{5})

\frac{( 3 x - 1 )}{2 x + 1}

y = \frac{2 x + 3}{x}

What is the inverse of y=(-4x^2+28x+31)/(16) ?
The inverse of y=(-4x^2+28x+31)/(16) is -(-7+4sqrt(-x+5))/2 ,(4sqrt(-x+5)+7)/2