What is the inverse of g(x)=4x^2+2 ?

The inverse of g(x)=4x^2+2 is (sqrt(x-2))/2 ,-(sqrt(x-2))/2

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inverse of g(x)=4x^2+2

inverse

g (x) = 4 x^{2} + 2

\frac{x - 2}{2}, - \frac{x - 2}{2}

Solution steps

y = 4 x^{2} + 2

Replace

x

with

y

x = 4 y^{2} + 2

Solve for

y, x = 4 y^{2} + 2

\frac{x - 2}{2}, - \frac{x - 2}{2}

g (x) = 4 x^{2} + 7

f (x) = \frac{x + 8}{4}

y = 3 - \frac{( x - 1 ) ^{2}}{3}

x^{2} - x + 6

2 cos (\frac{2 π t}{3})

What is the inverse of g(x)=4x^2+2 ?
The inverse of g(x)=4x^2+2 is (sqrt(x-2))/2 ,-(sqrt(x-2))/2