What is the inverse of y=3-((x-1)^2)/3 ?

The inverse of y=3-((x-1)^2)/3 is sqrt(-3x+9)+1,-sqrt(-3x+9)+1

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inverse of y=3-((x-1)^2)/3

inverse

y = 3 - \frac{( x - 1 ) ^{2}}{3}

- 3 x + 9 + 1, - - 3 x + 9 + 1

Solution steps

y = 3 - \frac{( x - 1 ) ^{2}}{3}

Replace

x

with

y

x = 3 - \frac{( y - 1 ) ^{2}}{3}

Solve for

y, x = 3 - \frac{( y - 1 ) ^{2}}{3}

- 3 x + 9 + 1, - - 3 x + 9 + 1

x^{2} - x + 6

2 cos (\frac{2 π t}{3})

f (x) = lo g_{\frac{1}{2}} (2 y) + 3

f (x) = \frac{( 4 x - 7 )}{2 x + 3}

What is the inverse of y=3-((x-1)^2)/3 ?
The inverse of y=3-((x-1)^2)/3 is sqrt(-3x+9)+1,-sqrt(-3x+9)+1