What is the inverse of y=-3x^2+100x+1 ?

The inverse of y=-3x^2+100x+1 is -(-50+sqrt(-3x+2503))/3 ,(sqrt(-3x+2503)+50)/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of y=-3x^2+100x+1

inverse

y = - 3 x^{2} + 100 x + 1

- \frac{- 50 + - 3 x + 2503}{3}, \frac{- 3 x + 2503 + 50}{3}

Solution steps

y = - 3 x^{2} + 100 x + 1

Replace

x

with

y

x = - 3 y^{2} + 100 y + 1

Solve for

y, x = - 3 y^{2} + 100 y + 1

- \frac{- 50 + - 3 x + 2503}{3}, \frac{- 3 x + 2503 + 50}{3}

f (x) = 19 x^{2} - 17

f (x) = 8 x - 2 + 5

f (x) = \frac{6}{1 - x}

(21) (21)

\frac{y ^{2}}{4}

What is the inverse of y=-3x^2+100x+1 ?
The inverse of y=-3x^2+100x+1 is -(-50+sqrt(-3x+2503))/3 ,(sqrt(-3x+2503)+50)/3