What is the inverse of f(x)=e^{x^2+1} ?

The inverse of f(x)=e^{x^2+1} is sqrt(ln(x)-1),-sqrt(ln(x)-1)

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inverse of f(x)=e^{x^2+1}

inverse

f (x) = e^{x^{2} + 1}

ln (x) - 1, - ln (x) - 1

Solution steps

y = e^{x^{2} + 1}

Replace

x

with

y

x = e^{y^{2} + 1}

Solve for

y, x = e^{y^{2} + 1}

ln (x) - 1, - ln (x) - 1

f (x) = 2 (x - 1)^{3} + 6

f (x) = 2 (x - 1)^{3} + 3

2 + 3

\frac{- \frac{3}{5} x + 15}{2}

f (x) = 2 + \frac{4 x}{3}

What is the inverse of f(x)=e^{x^2+1} ?
The inverse of f(x)=e^{x^2+1} is sqrt(ln(x)-1),-sqrt(ln(x)-1)