What is the inverse of f(x)=-2(x+2)^{1/3}-1 ?

The inverse of f(x)=-2(x+2)^{1/3}-1 is (-x^3-3x^2-3x-1)/8-2

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inverse of f(x)=-2(x+2)^{1/3}-1

inverse

f (x) = - 2 (x + 2)^{\frac{1}{3}} - 1

\frac{- x ^{3} - 3 x ^{2} - 3 x - 1}{8} - 2

Solution steps

y = - 2 (x + 2)^{\frac{1}{3}} - 1

Replace

x

with

y

x = - 2 (y + 2)^{\frac{1}{3}} - 1

Solve for

y, x = - 2 (y + 2)^{\frac{1}{3}} - 1

\frac{- x ^{3} - 3 x ^{2} - 3 x - 1}{8} - 2

y = 2 x - 8

- \frac{3}{s ^{2} - 6 s + 13}

\frac{2 x ^{2} + 1}{3 x - 2}

3 x^{2} - 27

lo g_{10} (x - 2) - 4

What is the inverse of f(x)=-2(x+2)^{1/3}-1 ?
The inverse of f(x)=-2(x+2)^{1/3}-1 is (-x^3-3x^2-3x-1)/8-2