What is the inverse of y= 3/4 sqrt(2/3 x)-4/9 ?

The inverse of y= 3/4 sqrt(2/3 x)-4/9 is (8(81x^2+72x+16))/(243)

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inverse of y= 3/4 sqrt(2/3 x)-4/9

inverse

y = \frac{3}{4} \frac{2}{3} x - \frac{4}{9}

\frac{8 ( 81 x ^{2} + 72 x + 16 )}{243}

Solution steps

y = \frac{3}{4} \frac{2}{3} x - \frac{4}{9}

Replace

x

with

y

x = \frac{3}{4} \frac{2}{3} y - \frac{4}{9}

Solve for

y, x = \frac{3}{4} \frac{2}{3} y - \frac{4}{9}

\frac{8 ( 81 x ^{2} + 72 x + 16 )}{243}

f (x) = 2^{(x)} + 5

f (x) = \frac{8}{x - 4}

lo g_{10} (x + 2) + lo g_{10} (5)

f (x) = \frac{1}{3} lo g_{2} (x)

\frac{1}{2} x - \frac{4}{5}

What is the inverse of y= 3/4 sqrt(2/3 x)-4/9 ?
The inverse of y= 3/4 sqrt(2/3 x)-4/9 is (8(81x^2+72x+16))/(243)