What is the inverse of log_{10}(x+2)+log_{10}(5) ?

The inverse of log_{10}(x+2)+log_{10}(5) is 2^x*5^{-1+x}-2

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inverse of log_{10}(x+2)+log_{10}(5)

inverse

lo g_{10} (x + 2) + lo g_{10} (5)

2^{x} \cdot 5^{- 1 + x} - 2

Solution steps

y = lo g_{10} (x + 2) + lo g_{10} (5)

Replace

x

with

y

x = lo g_{10} (y + 2) + lo g_{10} (5)

Solve for

y, x = lo g_{10} (y + 2) + lo g_{10} (5)

2^{x} \cdot 5^{- 1 + x} - 2

f (x) = \frac{1}{3} lo g_{2} (x)

\frac{1}{2} x - \frac{4}{5}

cot (2 x)

f (x) = 4 - x

f (x) = (15 x + 1)^{2}

What is the inverse of log_{10}(x+2)+log_{10}(5) ?
The inverse of log_{10}(x+2)+log_{10}(5) is 2^x*5^{-1+x}-2