What is the inverse of f(x)=(x^2+2)/(x-1) ?

The inverse of f(x)=(x^2+2)/(x-1) is (x+sqrt(x^2-4(2+x)))/2 ,(x-sqrt(x^2-4(2+x)))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=(x^2+2)/(x-1)

inverse

f (x) = \frac{x ^{2} + 2}{x - 1}

\frac{x + x ^{2} - 4 ( 2 + x )}{2}, \frac{x - x ^{2} - 4 ( 2 + x )}{2}

Solution steps

y = \frac{x ^{2} + 2}{x - 1}

Replace

x

with

y

x = \frac{y ^{2} + 2}{y - 1}

Solve for

y, x = \frac{y ^{2} + 2}{y - 1}

\frac{x + x ^{2} - 4 ( 2 + x )}{2}, \frac{x - x ^{2} - 4 ( 2 + x )}{2}

f (y) = arcsin (x)

f (x) = \frac{( 3 x - 7 )}{5}

f (x) = lo g_{10} (4^{x + 2})

f (x) = 1 - (x - 1)^{2}

f (x) = \frac{x}{22}

What is the inverse of f(x)=(x^2+2)/(x-1) ?
The inverse of f(x)=(x^2+2)/(x-1) is (x+sqrt(x^2-4(2+x)))/2 ,(x-sqrt(x^2-4(2+x)))/2