What is the inverse of f(x)=sqrt(1-(x-1)^2) ?

The inverse of f(x)=sqrt(1-(x-1)^2) is 1-sqrt(-x^2+1),sqrt(-x^2+1)+1

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inverse of f(x)=sqrt(1-(x-1)^2)

inverse

f (x) = 1 - (x - 1)^{2}

1 - - x^{2} + 1, - x^{2} + 1 + 1

Solution steps

y = 1 - (x - 1)^{2}

Replace

x

with

y

x = 1 - (y - 1)^{2}

Solve for

y, x = 1 - (y - 1)^{2}

1 - - x^{2} + 1, - x^{2} + 1 + 1

f (x) = \frac{x}{22}

4^{x + 3} - 2

\frac{6 s - 5}{s ^{2} + 7}

\frac{3}{9 s ^{2} + 12 s + 13}

f (x) = \frac{x}{2} - 7

What is the inverse of f(x)=sqrt(1-(x-1)^2) ?
The inverse of f(x)=sqrt(1-(x-1)^2) is 1-sqrt(-x^2+1),sqrt(-x^2+1)+1