What is the inverse of (6s-5)/(s^2+7) ?

The inverse of (6s-5)/(s^2+7) is (3+sqrt(-s(7s+5)+9))/s ,(3-sqrt(-s(7s+5)+9))/s

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inverse of (6s-5)/(s^2+7)

inverse

\frac{6 s - 5}{s ^{2} + 7}

\frac{3 + - s ( 7 s + 5 ) + 9}{s}, \frac{3 - - s ( 7 s + 5 ) + 9}{s}

Solution steps

y = \frac{6 s - 5}{s ^{2} + 7}

Replace

s

with

y

s = \frac{6 y - 5}{y ^{2} + 7}

Solve for

y, s = \frac{6 y - 5}{y ^{2} + 7}

\frac{3 + - s ( 7 s + 5 ) + 9}{s}, \frac{3 - - s ( 7 s + 5 ) + 9}{s}

\frac{3}{9 s ^{2} + 12 s + 13}

f (x) = \frac{x}{2} - 7

f (x) = 2 (\frac{1}{x - 5})

7^{0.5}

What is the inverse of (6s-5)/(s^2+7) ?
The inverse of (6s-5)/(s^2+7) is (3+sqrt(-s(7s+5)+9))/s ,(3-sqrt(-s(7s+5)+9))/s