What is the inverse of (3x-1/5)(3x+1/5) ?

The inverse of (3x-1/5)(3x+1/5) is (sqrt(25x+1))/(15),-(sqrt(25x+1))/(15)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of (3x-1/5)(3x+1/5)

inverse

(3 x - \frac{1}{5}) (3 x + \frac{1}{5})

\frac{25 x + 1}{15}, - \frac{25 x + 1}{15}

Solution steps

y = (3 x - \frac{1}{5}) (3 x + \frac{1}{5})

Replace

x

with

y

x = (3 y - \frac{1}{5}) (3 y + \frac{1}{5})

Solve for

y, x = (3 y - \frac{1}{5}) (3 y + \frac{1}{5})

\frac{25 x + 1}{15}, - \frac{25 x + 1}{15}

y = 0.4 x - 19

y = \frac{x}{( 1 - x ^{2} )}

f (x) = \frac{6 x + 2}{5 x - 7}

f (x) = - \frac{1}{3 ( \frac{1}{3 x} )}

sin (0.925)

What is the inverse of (3x-1/5)(3x+1/5) ?
The inverse of (3x-1/5)(3x+1/5) is (sqrt(25x+1))/(15),-(sqrt(25x+1))/(15)