What is the inverse of ((7x-3))/((7x+1)) ?

The inverse of ((7x-3))/((7x+1)) is (-3-x)/(7(-1+x))

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inverse of ((7x-3))/((7x+1))

inverse

\frac{( 7 x - 3 )}{( 7 x + 1 )}

\frac{- 3 - x}{7 ( - 1 + x )}

Solution steps

y = \frac{7 x - 3}{7 x + 1}

Replace

x

with

y

x = \frac{7 y - 3}{7 y + 1}

Solve for

y, x = \frac{7 y - 3}{7 y + 1}

\frac{- 3 - x}{7 ( - 1 + x )}

f (x) = \frac{3 x - 9}{5 x - 10}

lo g_{10} (x^{3} + 8)

f (x) = x + x

\frac{4 x + 9}{x - 1}

f (x) = x^{2} + 3 x + 6

What is the inverse of ((7x-3))/((7x+1)) ?
The inverse of ((7x-3))/((7x+1)) is (-3-x)/(7(-1+x))