What is the inverse of log_{10}(x^3+8) ?

The inverse of log_{10}(x^3+8) is cube root of 10^x-8

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inverse of log_{10}(x^3+8)

inverse

lo g_{10} (x^{3} + 8)

Solution steps

y = lo g_{10} (x^{3} + 8)

Replace

x

with

y

x = lo g_{10} (y^{3} + 8)

Solve for

y, x = lo g_{10} (y^{3} + 8)

f (x) = x + x

\frac{4 x + 9}{x - 1}

f (x) = x^{2} + 3 x + 6

\frac{2 x ^{2} - 12 x + 17}{x ^{2} - 8 x + 16}

f (x) = x^{2} + 3 x + 3

What is the inverse of log_{10}(x^3+8) ?
The inverse of log_{10}(x^3+8) is cube root of 10^x-8