What is the inverse of f(x)=x^2+3x+3 ?

The inverse of f(x)=x^2+3x+3 is (-3+sqrt(4x-3))/2 ,(-3-sqrt(4x-3))/2

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inverse of f(x)=x^2+3x+3

inverse

f (x) = x^{2} + 3 x + 3

\frac{- 3 + 4 x - 3}{2}, \frac{- 3 - 4 x - 3}{2}

Solution steps

y = x^{2} + 3 x + 3

Replace

x

with

y

x = y^{2} + 3 y + 3

Solve for

y, x = y^{2} + 3 y + 3

\frac{- 3 + 4 x - 3}{2}, \frac{- 3 - 4 x - 3}{2}

f (x) = - x_{+ 4}

\frac{1}{2} ln (1 - x)

f (x) = \frac{x - 1}{2 ( x + 1 )}

f (x) = x \cdot x - 4 \cdot x + 4

f (x) = x - x

What is the inverse of f(x)=x^2+3x+3 ?
The inverse of f(x)=x^2+3x+3 is (-3+sqrt(4x-3))/2 ,(-3-sqrt(4x-3))/2