What is the inverse of f(x)=(x-1)/(2(x+1)) ?

The inverse of f(x)=(x-1)/(2(x+1)) is (-1-2x)/(2x-1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=(x-1)/(2(x+1))

inverse

f (x) = \frac{x - 1}{2 ( x + 1 )}

\frac{- 1 - 2 x}{2 x - 1}

Solution steps

y = \frac{x - 1}{2 ( x + 1 )}

Replace

x

with

y

x = \frac{y - 1}{2 ( y + 1 )}

Solve for

y, x = \frac{y - 1}{2 ( y + 1 )}

\frac{- 1 - 2 x}{2 x - 1}

f (x) = x \cdot x - 4 \cdot x + 4

f (x) = x - x

f (x) = \frac{1}{1 - x ^{2}}

f (x) = x^{2} + y^{2} = 16

f (x) = 2 (- 1 + e^{t})

What is the inverse of f(x)=(x-1)/(2(x+1)) ?
The inverse of f(x)=(x-1)/(2(x+1)) is (-1-2x)/(2x-1)