What is the inverse of f(x)=sqrt(x)-x ?

The inverse of f(x)=sqrt(x)-x is (-2x+1+sqrt(-4x+1))/2 ,(-2x+1-sqrt(-4x+1))/2

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inverse of f(x)=sqrt(x)-x

inverse

f (x) = x - x

\frac{- 2 x + 1 + - 4 x + 1}{2}, \frac{- 2 x + 1 - - 4 x + 1}{2}

Solution steps

y = x - x

Replace

x

with

y

x = y - y

Solve for

y, x = y - y

\frac{- 2 x + 1 + - 4 x + 1}{2}, \frac{- 2 x + 1 - - 4 x + 1}{2}

f (x) = \frac{1}{1 - x ^{2}}

f (x) = x^{2} + y^{2} = 16

f (x) = 2 (- 1 + e^{t})

f (x) = \frac{5 x + 2}{9 x - 4}

\frac{6 x}{36 - x ^{2}}

What is the inverse of f(x)=sqrt(x)-x ?
The inverse of f(x)=sqrt(x)-x is (-2x+1+sqrt(-4x+1))/2 ,(-2x+1-sqrt(-4x+1))/2